3c^2-12c+9=0

Solution for 3c^2-12c+9=0 equation:

Simplifying
3c2 + -12c + 9 = 0

Reorder the terms:
9 + -12c + 3c2 = 0

Solving
9 + -12c + 3c2 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '3'.
3(3 + -4c + c2) = 0

Factor a trinomial.
3((1 + -1c)(3 + -1c)) = 0

Ignore the factor 3.
Subproblem 1
Set the factor '(1 + -1c)' equal to zero and attempt to solve:

Simplifying
1 + -1c = 0

Solving
1 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1c = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1c = 0 + -1
-1c = 0 + -1

Combine like terms: 0 + -1 = -1
-1c = -1

Divide each side by '-1'.
c = 1

Simplifying
c = 1
Subproblem 2
Set the factor '(3 + -1c)' equal to zero and attempt to solve:

Simplifying
3 + -1c = 0

Solving
3 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1c = 0 + -3
-1c = 0 + -3

Combine like terms: 0 + -3 = -3
-1c = -3

Divide each side by '-1'.
c = 3

Simplifying
c = 3
Solution
c = {1, 3}